PROTEOME-2 (Part 2)

Molecular biocoding of Prot P62258 14-3-3 protein epsilon, Homo sapiens

ALGORITHM

We shall now give some mathematical evidences that will prove that in the biochemistry of insulin there really is programmatic and cybernetic algorithm in which it is „recorded“, in the language of mathematics, how the molecule will be built and what will be the quantitative characteristics of the given genetic information.

Arithmetic progression

Step 1 (Amino acids from 1 to 255)

AC1 = 20 atoms; AC2 = 16 atoms; AC3 = 16 atoms;... AC255 = 20 atoms;

[AC1 + (AC1+ AC2) + (AC1+ AC2+ AC3)..., + (AC1+ AC2+ AC3..., + AC255)] = S1;

AC1 = APa1 = 20;

(AC1+ AC2) = (20+16) = APa2 = 36;

(AC1+ AC2+ AC3) = (20+16+16) = APa3 = 52;

(AC1+ AC2+ AC3..., + AC255) = APa255 = 4828 atoms;

APa1,2,3,n = Arithmetic progression of amino acids 1,2,3,n

[APa1+APa2+APa3)..., + APa255)] = (20+36+52…, + 4828) = 6624 024;

S1 = 624 024;

Example :

Arithmetic progression 1 (APa)

M	D	D	R	E	D	L	V	.	.	E	N	Q	Sum
20	16	16	26	19	16	22	19	.	.	19	17	20	4828
1	2	3	4	5	6	7	8	.	.	253	254	255	32640

I

M	D	D	R	E	D	L	V	.	.	E	N	Q	Sum
20	36	52	78	97	113	135	154	.	.	4791	4808	4828	624024
1	2	3	4	5	6	7	8	.	.	253	254	255	32640

(0+20) = 20; (20+16)=36; (20+16+16)=52; etc.

Step 2 (Amino acids from 255 to 1)

AC255 = 20 atoms; AC254 = 17 atoms; AC253 = 19 atoms;... AC1 = 20 atoms;

[AC255 + (AC255+ AC254) + (AC255+ AC254+ AC253)..., +

+AC255+AC254+AC253..., +AC1)] = S2;

AC255 = APb255 = 20;

(AC255+ AC254) = (20+17) = APb254 = 37;

(AC255+ AC254+ AC253) = (20+17+19) = APb253 = 56;

(AC255+ AC254+ AC253..., + AC255) = APb1 = 4828 atoms;

APb255,254,253, …,1 = Arithmetic progression of amino acids 255,254,253,…1;

[APb255+APb254+APb253)..., + APb1)] = (20+37+56…, + 4828) = 611 994;

S2 = 611 944;

Example:

Arithmetic progression 2 (APb)

Sum	M	D	D	.	.	E	D	E	N	Q
4828	20	16	16	.	.	19	16	19	17	20
32640	1	2	3	.	.	251	252	253	254	255

I

Sum	M	D	D	.	.	D	E	N	Q
611944	4828	4808	4792	.	.	72	56	37	20
32640	1	2	3	.	.	252	253	254	255

(0+20) = 20; (20+17)=37; (20+17+19)=56; etc.

Figure 2. Schematic representation of the arithmetic progression 1 and 2 from 1 to 255 and from 255 to 1.